Trigonometry

So I'm teaching myself trigonometry when I came across a problem I don't quite understand, could anyone clarify this, perhaps give me   a step by step solution?   If sin a = 3/4  and cos b = 2/3, then tan a + cot b = ?

step 1)  1.83

no its 2.0283 shit

How do you go about getting that answer though, I'm assuming an identity needs to be utilized, but which?

sin(a) = opp. / hyp. = 3/4
Therefore opposite length = 3, hypotenuse length = 4
That means adjacent side length = sqrt(7)
Therefore tan(a) = 3/sqrt(7)

Same process works for cot(b)

cos(b) = adj. / hyp. = 2/3
Therefore adjacent length = 2, hypotenuse length = 3
That means opposite length = sqrt(5)
Therefore cot(b) = 2/sqrt(5)

YOu can also do tan = sin/cos and cot = cos/sin so it is just a matter of fraction math to calculate

YOu can also do x = (y + z)s+n; where x is U, y is your education level, z is your vocabulary; s is STFU, and n is GTFO.
Now, if Trigonometry = x; and 4chan.org = y; thread = z then,
S = y-(x+z)
S = SAGE

  Name: Anonymous : 2008-06-02 13:33

    YOu can also do x = (y + z)s+n; where x is U, y is your education level, z is your vocabulary; s is STFU, and n is GTFO.
    Now, if Trigonometry = x; and 4chan.org = y; thread = z then,
    S = y-(x+z)
    S = SAGE

Fuck off anonymous, this is the science board not the troll board.  Now gtfo back to /b/ where your shitface-faggotry belongs.

I'd much rather smuther my shitty-ass faggotry all over your faces and see what response you monk-e's can do. OOO-OOH-OOH; HAA-HAAA-HAA-HAA.
*awaiting predictive animal natures*