Return Styles: Pseud0ch, Terminal, Valhalla, NES, Geocities, Blue Moon.

Pages: 1-

Formula for roots of higher polynomials?

Name: Anonymous 2008-03-23 18:00

Does anyone know of the formulas for roots of higher order polynomials (3+)?  We learned the quadratic formula in grade school but never heard of formulas for higher polynomials..  do they exist?

Name: Anonymous 2008-03-23 18:16

Do you know how the quadratic equation was calculated? If so complete the square except with..

ax^4 + bx^3 + cx^2 + dx + e = 0

Name: Anonymous 2008-03-23 18:19

They don't exist for most higher-order polynomials. They do for 3 and 4, though.

Name: Anonymous 2008-03-23 18:47

There's a very complicated one for cubics, and there's a super-duper complicated one for quartics. However, Niels Abel proved that no formula exists for quintics, and Evariste Galois proved that no formula exists for anything above quartics.

Just use Newton's method. It's easy, and it kicks ass.

Name: RedCream 2008-03-23 19:25

>>4
What is the basic idea behind the proof that no formula exists for quintics and above?  In other words, what is the common characteristic of these equations that makes them formula-constructible for up to quartics inclusive, yet not beyond that complexity?

Making the 4th power of complexity the demarcation point just seems like an arbitrary thing.

Name: Anonymous 2008-03-23 19:32

>>5
http://en.wikipedia.org/wiki/Galois_theory#Application_to_classical_problems
'"Why is there no formula for the roots of a fifth (or higher) degree polynomial equation in terms of the coefficients of the polynomial, using only the usual algebraic operations (addition, subtraction, multiplication, division) and application of radicals (square roots, cube roots, etc)?"'

Read, and stop being such a quasi-philosophical tit.

Name: Anonymous 2008-03-23 19:39

>>5
The fact is the A_n is normal for n>5, and thus S_n contains a simple, normal subgroup.

The reason that makes the equations unsolvable, is touched on by the wiki page on "Galois theory", but I'm not entirely certain myself how it follows.

Name: Anonymous 2008-03-23 19:59

>>4

How do you use Newton's Method to find complex roots?

Name: Anonymous 2008-03-23 20:09

Name: Anonymous 2008-03-23 20:36

>>7
Ahhh it's to do with that is it? One of my lecturers recently gave an awesome geometric proof of A_n's normality, based around the dodecahedron.

Name: RedCream 2008-03-23 22:21

>>6
Before you know, you have to admit that you DON'T KNOW.  That's why I asked -- I just didn't know.  The hostility of your response is simply uncalled for and reveals a boorishness and lack of social skill.

Just the same, I'll read up on Galois Theory and attempt to sense why Quintics+ are not formulizable.  While I'm doing that, you should consider your error and how you should better interact with people in the future.  Good day.

Name: Anonymous 2008-03-23 22:48

>>11
Actually, I called you a tit because, seeing your pretentious posting history, you're basically a tit. Also:
"Making the 4th power of complexity the demarcation point just seems like an arbitrary thing."
Yes, I'm sure years of formal mathematical theory went into proving that something they made the hell up was true.

Name: Anonymous 2008-03-23 23:05

>>11

You have used the word "boorishness" in a sentence.  Your argument is invalid.

Name: Anonymous 2008-03-24 0:10

>>4
You make it sound like Abel's and Galois's results were different. They weren't; they were identical, but discovered independently (I think it was Galois's work that was ignored for quite a while). It's pretty easy to see that if there is no general solution to the quintic, there is no general solution to any degree greater than 4. Suppose there is a general solution for degree k > 4; then k >= 5. Given a 5th degree polynomial f(x), take x^(k-5)*f(x). This is kth degree, and therefore solvable with the general solution for degree k polynomials, but the solutions will be the solutions of f(x) along with k-5 0's.

Name: RedCream 2008-03-24 2:51

>>12
Actually, you called me a tit since you despise open inquiry and fairly well give blowjobs to prominent math icons as a form of hero worship.  Real scholarship is egoless.  It's going to take a lot of time for you to understand that, I can tell.

As for what is formal and that is true, I merely noted that the demarcation point seems arbitrary.  I didn't say that it WAS ... only that it seemed.  That's a part of free inquiry -- which we've established you despise while your mouth is O-ring sealed around the cock of a Nobel Laureate.

In the future, just try to suspend that pointless ego of yours and just relate the information as you purport to understand it.  That's why these called these things "message boards".  You've been sending another message entirely.

While we're on the topic of what you purportedly understand, can you even RELATE in any terms whatsoever what the Galois Theory is?  Pointing to a wiki is a great way to show that you really don't understand the conclusive structure in the first place.  In fact, anyone who is unable to relate in lesser terms what they supposedly know about higher organization, probably doesn't even understand the topic in the first place.  People who truly understand something, largely are able to deliver instruction in that topic to a wider audience.  You've failed to do that.  My reasonable conclusion about that is obvious.

Name: 4tran 2008-03-24 4:46

>>15
This is math, not science, so
Nobel Laureate -> Field Medalist

Name: Anonymous 2008-03-24 11:03

>>10


Geometrical proofs aren't proofs, it's just pictures and hand waving.

Name: Anonymous 2008-03-24 17:31

>>17
Hehe, it wasn't that sort of geometric proof, but it did use the geometric properties of the shape. SORRY FOR THE CONFUSION EVERYONE.

Name: RedCream 2008-03-24 19:32

>>16
Oops.  Thx.

Don't change these.
Name: Email:
Entire Thread Thread List