f(x) = cos^2(x) + cos(x)
M = maximum of f(x)
m = minimum of f(x)
a = M - m = ?
Name:
Anonymous2008-03-23 17:04
Seriously? Learn to differentiate.
On the interval 0<x<2π, for simplicity's sake:
f'(x) = -2 cos x sin x - sin x
0 = -2 cos x sin x - sin x
x, then, equals 0 and 2π/3 (there are an infinite number of solutions, but these are the only two you really need).
M = f(0) = 2
m = f(2π/3) = -1/4
a = M - m = 2 + 1/4 = 9/4
Name:
Anonymous2008-03-23 19:12
>>2
Excellent, many thanks! Seriously? Learn to differentiate.
I can't say I've had much previous experience with differentiation of any kind. And by that I mean none at all. ;_; But I now understand this one, so thanks!
Are you (or anyone) up for a second one?
f:R->R
f(x)= sin^2x - x^2 + (x^4)/3
f(n+1)(x) = ? (That is, f differentiated or derived (whichever is correct in English) n+1 times.) where n>=4.
>>7
If I'm not correct about the former, I'm still right about the latter. Stop being such a bastard. Snobbery serves no function in tutoring or mentoring.
Name:
Anonymous2008-03-24 20:20
>>8
Let me get this right: The guy who thinks that America is about to implode is suddenly worried about mentoring and tutoring someone in math?
>>12 is not >>7
I am >>7 and I do hsve a Ph.D.
Since most of you don't have the mental capacity to understand what that means, disregard this statement.