Name:
Anonymous
2008-03-23 16:34
f(x) = cos^2(x) + cos(x)
M = maximum of f(x)
m = minimum of f(x)
a = M - m = ?
Name:
Anonymous
2008-03-23 17:04
Seriously? Learn to differentiate.
On the interval 0<x<2π, for simplicity's sake:
f'(x) = -2 cos x sin x - sin x
0 = -2 cos x sin x - sin x
x, then, equals 0 and 2π/3 (there are an infinite number of solutions, but these are the only two you really need).
M = f(0) = 2
m = f(2π/3) = -1/4
a = M - m = 2 + 1/4 = 9/4