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Math

Name: Logistic Growth 2008-03-02 19:08

How the fuck do i do this problem? I am so lost.

 A  certain wild animal preserve can support no more then 250 lowland gorillas. 25 were known to be in the preserve in 1970. In 1980, the population reached 58. If the growth is logistic, find the constants C,A, and K.

    y= C/1+Ae^-kt

Name: Anonymous 2008-03-02 20:01

You're an idiot.

You have C/1+A=250
C/1+Ae^-kt1 = 25
C/1+Ae^-k(t1+10) = 58

3 equations, 3 unknown, solve them.

Name: Anonymous 2008-03-03 0:35

.572

Name: Anonymous 2008-03-06 23:57

What do the variables represent though?

Name: Anonymous 2008-03-07 3:50

I imagine that t is time and y is number of gorillias.  Why is there a C/1?  Isn't that just C?

Name: Anonymous 2008-03-07 7:11

C/1

Name: Anonymous 2008-03-07 7:23

>>2
What do the constraints of the environment have to do with exponential growth... why does t = 0 at this point?

Name: Anonymous 2008-03-07 7:34

disregard that, I suck cocks

Name: Anonymous 2008-03-07 7:37

But wait, wtf, isn't that an equation for exponential growth?

Name: Anonymous 2008-03-07 7:47

and http://www.mathwords.com/l/logistic_growth.htm gives a logistic equation

I think ur doin somethin wrong.

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