;/

|log 2 (3x-1/3)|=|log 2 (5-2x/2)|
How does one go about solving such an equation?

>>2

protip, |log x| is not equal to log |x| in general.  like for any x in (0,1)

also, i think OP is noting log base 2 not log of 2 * some stuff. but eh.