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Name: Anonymous 2007-11-24 17:52

|log 2 (3x-1/3)|=|log 2 (5-2x/2)|
How does one go about solving such an equation?

Name: Anonymous 2007-11-24 18:10

log|2(3x-1/3)|=log|2(5-2x/2)|

10^log|2(3x-1/3)| = 10^log|2(5-2x/2)|
2(3x-1/3) = 2(5-2x/2)
3x-1/3 = 5-x
4x = 16/3
x= 4/3

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