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What's the derivative of e^x?

Name: Anonymous 2007-11-06 12:48

What is it?

Name: Anonymous 2007-11-06 12:58

Relative to what?

Name: Anonymous 2007-11-06 13:05

e^x.

Name: Anonymous 2007-11-06 13:47

dude... e is a constant (and a damn ugly one at that)

ln(e) = 1

Name: Anonymous 2007-11-06 13:47

Oh, and what >>2 said

Name: Anonymous 2007-11-06 15:43

what does e being a constant have to do with anything? e^x is the only function that is the derivative of itself., so yes, >>3 is right.

Name: Anonymous 2007-11-06 16:30

learn2calculus.

Name: Anonymous 2007-11-06 20:10

>>6
What >>7 said. >>3 is only right if you're differentiating with respect to x. If you integrate with respect to some other variable y, you get 0.

Name: Anonymous 2007-11-06 21:09

>>6
the entire family C*e^x are their own derivative, not just e^x.

Easy enough to prove: dy/dx=y -> dy/y=dx -> ln y=x+k -> y=e^(x+k)=C*e^x

Name: Anonymous 2007-11-06 21:40

>>6
0 is the derivative of itself.

Name: Anonymous 2007-11-06 22:26

>>9, this is >>6. That is my mistake, you are right. But if you know anything about differentiation, you should be able to figure it out.

And >>8, I did disregard that fact, because if you are honestly looking for the derivative with respect to y, you know absolutely no calculus. The only thing that you should be wondering about, if at all, is the derivative with respect to x.

Name: Anonymous 2007-11-07 1:46

>>11
Enjoy your complete lack of real-world experience with calculus, dickfuck.

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