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infinitesimals

Name: Anonymous 2007-11-03 20:30

Consider a, b, c infinitesimals such that
    a+b=c
Does it then hold that
    a=b=c
?

Name: Anonymous 2007-11-03 20:47

no

Name: Anonymous 2007-11-03 21:15

only if a = b = 0

Name: Anonymous 2007-11-03 22:13

Well then if .99... equals 1, then doesn't that have to hold?

Name: Anonymous 2007-11-03 22:21

No, for the same reason that infinity does not equal infinity.
Stop trying to apply algebra naively. Infinitesimals and infinities do not work this way.

Name: Anonymous 2007-11-04 6:44

however c+b=a like a+b=c

Name: Anonymous 2007-11-05 23:37

>>5

Actually, infinitesimals and infinities do work this way.  The problem with the line of reasoning in 4 is that 0.999... < 1 in the hyperreal numbers - equality only holds in the real numbers.

Name: Anonymous 2007-11-06 1:13

>>7
The problem with this is that some people will actually believe it.

Name: Anonymous 2007-11-06 1:24

>>7
You really want to start that troll again?  Seriously.  Kill yourself now.

Name: Anonymous 2007-11-06 23:52

Infintesimals only have a defined meaning in the hyperreal number system. Go pick up a copy of Nonstandard Analysis, fag.

Name: Anonymous 2007-11-07 1:35

FYI, hyperreal numbers have nothing to do with .9999=1, which holds in every (base 10) number system.  Troll moar plz.

All number systems work together and in the same way when it comes to algebra.  You can't honestly claim otherwise.  "Oh, I see I've got these irrational numbers here.  Better not use those with the integers.  Might fuck things up."  You can add 1 and an infinitesimal; the hyperreal system merely provides the notation with which to do this.

Your attempted use of hyperreal numbers to prove a givenly-false assertion is meaningless.  As >>5 said, infinities are not equal; nor are infinitesimals.  If x=y=z, then it cannot also be true that x+y=z, for the same reason that 1+1!=1.

Stop arguing and start learning.  lrn2research

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