Talor Polynomial

How do I find the quadratic Taylor polynomials about (0,0) for the following:

(x-y+1)^2

[e^(x)]cos(y)

and

e^[(-2x^2)-(y^2)]

Seriously, I need help on this, badly.  Can anyone of you anons, advice me on how to approach these problems?

There is a formula.

http://en.wikipedia.org/wiki/Taylor_series#Taylor_series_for_several_variables

if you don't want to chain rule the fuck out of yourself doing the derivations. simplify the terms as much as possible, then do taylor expansions for each term in the expression.

(x-y+1)^2 = x^2 -2xy +2x +y^2 +2y +1

so just add/subtract the firt few terms in the taylor expansions for each of those easy functions.

for the second just write the taylor series of e^x in one set of parenthesis and the cosy in another and put a multiplication sign between them. Fuck multiplying it out past 3 or four terms though, hopefully 2-3 terms in each is enough.

do the same thing for the third by noticing it is e^(-2^2) times e^-(y^2)

the link above is good too if you understand all the mathy terms.

in general, taylor series (around zero) are of the form.

f(t)= (1/0!)f(t=0) + (1/1!)f'(t=0)(t-0) + (1/2!)f''(t=0)(t-0)^2 + .. (1/m!)f(m derivatives)(t=0)(t-0)^m

m=0,1,2,3 ... infinity

some faggot named macluren (spelling) or something called dibs on taylor series around zero, so if you're asked to expand in terms of a macluren (spelling), it's just taylor's around zero.