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Wave equation

Name: Anonymous 2007-10-10 22:37

u_tt - 4 u_xx = 0

initial conditions: u(x,0) = 0, u_t(x,0) = 0
in R = {(x,t) | 0<=x<=1, t>=0}

boundary conditions: u(0,t) = 0, u_x(1,t) = f(t)
in t>=0

v(x,t) = u_t + 2 u_x
w(x,t) = u_t - 2 u_x

I know you are supposed to approximate u(x,t) but you can find v and w. What I really can't figure out is how to find u_t(1,t) and u_x(0,t).

I know you use d'Alembert formula to find u(x,t) with just the initial conditions but I have no idea how to do this with the boundary conditions. Can you refer me to how to do this with boundary condition and also, how do I finded out v(1,t) and w(0,t)?

Name: Anonymous 2007-10-11 0:38

Jeepers, I don't know

Name: Anonymous 2007-10-11 10:28

bummmp :[

Name: RedCream 2007-10-11 22:54

It's "utt-4uxx = 0", mathfag!

LEARN TO USE THE [sup] AND [sub] BBCODES!

Name: Anonymous 2007-10-12 7:19

o[sup]o[sup]o[sup]o[sup]o[sup]o[sup]o[sup]o

Name: RedCream 2007-10-13 0:40

LEARN TO USE THE CLOSURE CODES FOR BBCODES!  GOOGLE "BBCODE", MOTHERFUCKER, CAN YOU TYPE IT?

Name: Anonymous 2007-10-13 18:36

CAPS LOCK, CAN YOU HIT IT?

Name: RedCream 2007-10-13 18:48

GAYAIDSANUS, IT SOUNDS LIKE YOU HIT THAT WITH SOME REGULARITY!

Name: Anonymous 2007-10-15 23:04

*scatches head*
differential equations, right?
u-sub-t and u-sub-tt are first and second derivatives w/ respect to t and likewise for x?
sorry, im not familliar with what youre talking about, but one of the things i know about diff eq is that when it gets too hard, you  plug it into a computer... there are plenty of them out there... for a good amt of money... perhaps my diff eq course has failed me...

Name: Anonymous 2007-10-17 12:35

>>9
Yeah, differential equations.

Apparently, v and w are related to each other and yes I have to use a computer to solve this. Solving with the computer is pretty cool. I can change the initial/boundary values and end up with all kinds of crazy shapes.

Don't change these.
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