Can anyone solve this?
Name:
Anonymous
2007-10-01 20:34
ID:jvCnPWLD
I certainly can't.
Find the inverse function of:
((2e^x)-10)/((7e^x)+13)
Name:
Anonymous
2007-10-01 20:59
ID:KhQxFipE
x = ((2e^y)-10)/((7e^y)+13)
Name:
Anonymous
2007-10-01 21:12
ID:jvCnPWLD
Well, I can get that far... anyone can
Name:
Anonymous
2007-10-02 0:05
ID:b10ZaDcD
Ok are you searious?
y = ((2e^x)-10)/((7e^x)+13)
2e^x - 10 = 7e^xy + 13y
2e^x - 7e^xy = 13y + 10
e^x(2 - 7y) = 13y + 10
e^x = (13y + 10)/(2 - 7y)
x = ln(13y + 10) - ln(2 - 7y)
ONE INTERNETS PLX