differential equation of cheese
1
Name:
Anonymous
2007-09-23 17:57
ID:XM4X3M1H
(y+x) dy/dx = y use y=xu to solve
save me from evil problem lords!
2
Name:
Anonymous
2007-09-23 18:05
ID:n5cvFPom
um
dy/dx X = 1 so
2?
3
Name:
Anonymous
2007-09-23 18:12
ID:nO83moQo
(ux + x)(u + x du/dx) = xu
x(u+1)(u + x du/dx) = xu
(u+1)(u+x du/dx) = u
(u + x du/dx) = u/(u+1)
x du/dx = u/(u+1) - u
x du/dx = (u - u^2 - u)/(u+1)
1/x dx = (u+1)/(-u^2) du
4
Name:
Anonymous
2007-09-23 18:15
ID:koOqfoww
I was gonna solve that but the way you wrote it out is confusing and ambiguous as fuck
5
Name:
Anonymous
2007-09-23 18:19
ID:XM4X3M1H
>>3
i got to there but then what
6
Name:
Anonymous
2007-09-23 18:20
ID:nO83moQo
>>4
(y+x) => (xu + x)
dy/dx => (u + xdu/dx)
y => xu
Plug it all in
(xu + x)(u + xdu/dx) = xu
Reduce it all to
(1/x)dx = (u+1)/(-u^2) du
wth is ambiguous about that?
7
Name:
Anonymous
2007-09-23 18:22
ID:nO83moQo
>>5
Integrate both sides and plug in y/x for u. Then solve for y
8
Name:
4tran
2007-09-24 0:40
ID:Heaven
Right side is probably easier to integrate if reexpressed as
-[(1/u) + (1/u2 )] du
The result of that is probably a large mess...
9
Name:
Anonymous
2007-09-25 1:37
ID:vqhvgHJp
That's what you get when you make cheese with homogenized milk!
10
Name:
McPeePants
2007-09-26 0:06
ID:Ll7lFx+r
42
11
Name:
Anonymous
2007-09-26 1:29
ID:gXp6f4GK
9000