Sigh... Look, flame me for being stupid all you want but I still need an answer. Obviously, you do not wish to help so I'll just have to hope someone else does.
Name:
Anonymous2007-08-29 21:21 ID:FuBP5vb7
Do you know how to solve a quadratic equation?
Name:
Anonymous2007-08-29 21:26 ID:syyzMCKW
sqrt(u - 3) = u - 5
u - 3 = u^2 -10u + 25
0 = u^2 - 11u + 28
0 = (u -4)(u - 7)
u = 4 and u = 7
Plug them em into the original equation to check for extraneous roots. With u = 4 you get 1 = -1, so you can throw that one out. With u = 7 you get 2 = 2. So u = 7.
Name:
Anonymous2007-08-29 21:26 ID:xqJYApfe
I'll say no, since I'm not sure what a quadratic equation can manifest itself as.
No, I am not trolling. I am trying to learn, but the material the school supplied me with is little more than numbers. No real explanation to why the formulas work the way they do.