Name:
Anonymous
2007-04-19 15:09
ID:X0KRFjNi
It's crying more with :`(
Name:
Anonymous
2007-04-22 23:30
ID:3o42ZU5D
Bryce Bolin
7..7 (a)
There exist no subfield K of C with R ⊂ K ⊂ C and R =/= K =/= C.
a,b € R
a+b € R, K,C, as defined for the confines above with R,K and C being fields.
b(i) = bi € K, C
(b^-1)bi = i; i € K, C
(b)i = bi
(a) + bi = a + bi
a + bi € C, K but not for R
So with R ⊂ K ⊂ C, it is not possible for K to be a subfield of C.
Name:
Anonymous
2009-03-18 2:46
The word pirahna, is all I can think of that rhymes with marijuana
Marijuana MUST be legalized.