i have this riduculous qustion....
two tracking stations 20 m apat, measure the angles of elevation of a rocket that was launched. from station a, the angle of elevation is 41 degrees; from sation b it is 75 degrees. what is the altitude of the rocket, to the nerest tenth
C
^
/|\
/ | \
/ | \
/ | \
B<_75__|_______41>
D
plz help
Name:
Anonymous2007-04-18 19:39 ID:KVPfscXJ
yes, that's pretty ridiculous. try harder.
Name:
Anonymous2007-04-18 20:08 ID:B71BPDpg
underage b&
Name:
Anonymous2007-04-18 21:53 ID:asbHGcdT
okay, let altitude of rocket be h. a is distance from station a to right below the rocket. Same for b. Apparently the ground is 1 dimensional if I follow the diagram there.
h/a = tan 41
h/b = tan 75
a + b = 20
Solve for h.
Name:
Anonymous2007-04-19 1:07 ID:OAwacZyL
The height of the rocket = (20/cos(26º))sin(41º)sin(75º) ≈ 14.101214005174410452295201629320274304784929791725907218028808999657728184124
615990285568667058527844329851185434726709865032232772826961399707996019665996
355863912701687889501142763628075115460203309060154960345442368823756295882960
9429655194943473656741535070294657826025723324229893336406819520419
Name:
Anonymous2007-04-20 18:30 ID:1pIh2dH1
"Degrees"?
UNDERAGE BAMPERSAND
Name:
Anonymous2007-04-20 20:19 ID:Jxfi5Ajx
It's a schooner
Name:
Anonymous2007-04-20 20:23 ID:5kM4QiH1
WHAT THE FUCK IS THAT SUPPOSED TO MEAN?
Name:
Anonymous2009-03-18 2:28
I'm feeling really keen, for some of that good ol' green