Name: Anonymous 2007-03-21 1:44 ID:HdIbn/18
Have at you, /sci/
Let x be a positive integer. Then
x^2 = x + x + ... + x (x times)
Differentiate with respect to x:
2x = 1 + 1 + ... + 1 (x times)
2x = x.
Let x = 1.
Thus, 2 = 1.
Let x be a positive integer. Then
x^2 = x + x + ... + x (x times)
Differentiate with respect to x:
2x = 1 + 1 + ... + 1 (x times)
2x = x.
Let x = 1.
Thus, 2 = 1.