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inequalities

halp.

Give the interval solution

A) 5/x < 3/4

B) 4/x -3 > 2/x - 7

x=0

Alternatively, x=3

A) 5 < 3x/4, so 20 < 3x, so 20/3 < x is the solution set
B) 4 - 3x > 2 - 7x, so 4 + 4x > 2, so 4x > -2, so x > -1/2 is the solution set.

>>4 the interval solution.

A) multiply by 4, divide by 20: x < 3/20, x = ]-inf;3/20[

B) add 7 x, subtract 4, divide by 4: x > -1/2, x = ]-1/2;inf[

>>5
"]-inf;3/20["

x = 14/100, then 5/x = 35 + 5/7 > 3/4.

14/100 < 3/20.

Fail.

>>4
Forgot to mention, this also fails for not taking into account that multiplying both sides by x will flip the sign if x < 0.

inequalities in American society today

>>6

afaik

14/100 < 15/100

>>9
Yes, which is why 14/100 is in ]-inf, 3/20[ = ]-inf, 15/100[.