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Proof of 1 Not equal 0.999...

Name: FrozenVoid 2007-03-01 8:54 ID:fPuNCwa3

0*infinity=(0+0+0+0...)=0 (x+0=x x=0)
1=0.999... (agreed) 1-0.999...=0
(type 1) 1-0.999...=(1/10)*(1/10)*(1/10)... (from division by 10, 1-0.9 etc)
ab=0 if a or b=0; 1/10=0 ;10*1/10=10*0 ;1=0 ;x*1=x*0 ;x=0
(type 2) (1/10)*(1/10)*(1/10) ...=(1/10)^infinity=1/infinity=0
1/infinity=0 then 0*infinity=1 bu 0*infinity=0 ;1=0 ;x*1=x*0; x=0
Every number equals zero .(by 1=0.999...)

Name: Anonymous 2007-03-03 22:08 ID:S1Jh/6m3

>>33
Stop being fucking absurd
"0*infinity=(0+0+0+0...)=0 "
Again, INFINITY IS NOT A FUCKING NUMBER, even if we consider the extension of reals, 0*infinity is indetermined. Your loved wikipedia will show it to you http://en.wikipedia.org/wiki/Infinity

1=0.999... (agreed) 1-0.999...=0
Equation Assumed to be true,be we show the absurdity of it in the following transformation. Difference between equals is zero

"ab=0 if a or b=0; 1/10=0 ;10*1/10=10*0 ;1=0 ;x*1=x*0 ;x=0
The multiplication results is zero,only is of one of the members is zero."
Total failure, ab are just 2 elements, and you have infinite of them, and no, you cant group infinite elements..."

"1/infinity=0 then 0*infinity=1 bu 0*infinity=0 ;1=0 ;x*1=x*0; x=0"
RIIIIIIIIIGHT, again, infinity is not a number, and, even if we consider a extension of reals, infinity/infinity is indetermined.

Now, quit math and go kill yourself

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