(26/75x^4)(3x^3/52y)(25y^2) = ?

(26/75x^4)(3x^3/52y)(25y^2) = ?

y/2x

Thank you anon.

= 1/2*y*x^7

(%i1) (26/75*x^4)*(3*x^3/52*y)*(25*y^2);
(%o1) (x^7*y^3)/2
(%i2) (26/(75*x^4))*(3*x^3/(52*y))*(25*y^2);
(%o2) y/(2*x)
(%i3) (26/75*x^4)*(3*x^3/(52*y))*(25*y^2);
(%o3) (x^7*y)/2

42

(26/75x^4)(3x^3/52y)(25y^2

=

26          3x^3         
-----   *  ------  *  25y^2
75x^4       52y


you then use the rule of division, a    c       a*c
                                   -- * --  =  -----
                                   b    d       b*d

26*3x^3                  26*25*3*x^3*y^2
--------   *   25y^2  = ----------------
5x^4*52y                    5*x^4*52*y


then factor out the x's and y's, multiply everywhere etc.

   1950*y      195*y     15    y
=  -------  =  -----  =  -- * ----
   260*x        26*x      2    x

>>7
wrong, idiot

You dropped the 7 from 75

3x^3*25y^2*26/52y*75x^4=1950*x^3*y^2/3900y*x^4
reducing by 1950=x^3*y^2/2y*x^4
reducing by x^3=y^2/2y*x
reducing by y=y/2x