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I have a serious problem.... with e

Name: Anonymous 2007-02-16 23:21

First, I lay down the following theorem:

e^(pi*i) = -1

Anyone will accept this as truth, and a calculator will verify it.

By laws of exponents:

(e^(pi))^i = -1

By definition:

i = sqrt(-1) = (-1)^(1/2)

So again by law of exponents:

((e^pi)^(-1))^(1/2) = -1

To help (parenthesis may be causing confusion), this is pronounced:

quantity e to the pi, to the negative one, to the one half, equals negative one.

Here's where the confusion begins. Square both sides.

( ((e^pi)^(-1))^(1/2) )^2 = ( -1 )^2
(e^pi)^(-1) = 1

As we know, anything to the negative first power is simply an inverse (for instance- 2^(-1) = 1/2)

1/(e^pi) = 1

e^pi is a constant.

2.71828^3.14159 = 23.14069

Therefore by Euler's formula:

e^(pi*i) = -1
1/23.14069 = 1

Name: Anonymous 2007-02-16 23:31 (sage)

((e^pi)^(-1))^(1/2) = -1
moar like (e^pi)^((-1)^(1/2)) = -1 amirite

also a lot of laws are only valid for the reals, not for complex numbers. but i'm too lazy to look up whether you're using any of those.

Name: 4tran 2007-02-18 12:18

>>1
"So again by law of exponents:

((e^pi)^(-1))^(1/2) = -1"

epic fail

2^(3^2) = 2^9 = 512
(2^3)^2 = 8^2 = 64

(e^(pi))^i = (e^pi)^[(-1)^(1/2)]

Name: Anonymous 2007-02-18 14:33

yeah youre doing something wrong, either parentheses in the wrong spot, or using exponents wrong with complex numbers

Name: Anonymous 2007-02-18 21:30

>>2
>>3

These guys are correct, although a lot of people tend to have trouble with this. It's important that you're understanding the laws and not just doing them.

Name: Anonymous 2007-02-19 6:04

Raising powers isn't associative.

Name: Anonymous 2007-02-19 10:49

I call it simon.

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