It's zero. When you factor it, you get 1/(x^3 + b^3), so when x -> b, 1/(x^3 + b^3) -> 1/(2b^3), and since b =/= 0, 2b^3 cannot equal zero, and therefore 1/(2b^3) -> 1/0, and by definition lim of 1/n as n -> 0 is 0, thus 1/(2b^3) -> 0.
Name:
Anonymous2007-02-04 15:26
>>3
Uh, what makes you think 1/(2b^3) -> 1/0? The limit is just 1/(2b^3), since we don't know anything about b except that it is not 0.
Name:
Anonymous2007-02-04 15:27
>>3
also...
"and by definition lim of 1/n as n -> 0 is 0"