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Need help

Name: Anonymous 2006-11-22 21:28

4 digit passcode (note the date is European format, D/M/Y)

First digit is the square root of my birthday, 9 January, divided by three plus six.

Second digit is four plus seven minus the the sq. root of my b-day

Third digit is square root of b-day + actual date of D-day

Last is the 3rd digit minus the 2nd one.

Name: Anonymous 2006-11-22 21:36

7891

Name: Anonymous 2006-11-22 21:39

...wtf?

I tried didn't work, apparently the hint was:

Perhaps 1 was the third digit, while 2 was added onto the fourth digit...

Name: Anonymous 2006-11-22 21:47

3rd Digit. 3+9 = 12

How'd you end up with 9

Name: Anonymous 2006-11-22 21:59

i used the actual date of d-day, june 6, 1944

Name: Anonymous 2006-11-22 22:02

Oops, I meant B-day. I mistyped that

Name: Anonymous 2006-11-22 22:16

>>6
but yes i noticed 12 is not a one digit number, and if its < 8 then the fourth digit is negative.  these instructions are not clear.

Name: Anonymous 2006-11-22 22:30

The instructions, word for word:

Now it's the square root of my birthday (9th of January), divided by three, add six. The second digit is four plus seven minus the square root of my birthday. The third digit it the square root of my birthday, plus the actual date of my birthday, the 9th. The final digit is the third digit minus the second digit.

Name: Anonymous 2006-11-23 0:28

Um? How is digit 3 supposed to be one?

Name: Anonymous 2006-11-23 0:29

W00t - last clue I got says that negatives WILL be result

Name: Anonymous 2006-11-23 4:21

First digit: Sq.rt.9 = 3/3 = 1+6 = 7
Digit two: 4+7=11 - 3 = 8
Digit three: 1? What? according to the clue, right?
Digit 4: = -7? Since negatives are accepted, added 2 is -5?

so, 7815?

Name: Anonymous 2006-11-24 17:03

You guys aren't taking into consideration that there are two equally correct answers to a square root problem.

Square root of 9 is (3, -3)

3^2 = 9
-3^2 = 9

As is, the question doesn't give you enough information to really get a definative answer, unless you want to go through trial and error and plug in 3 and -3 in all the spots it asks for a square root... and maybe get a few possible answers.

Its, imo, a shitty question for being vague about its instructions.

Name: Anonymous 2006-11-25 7:44

So, is √-1 both i and -i?

Name: Anonymous 2006-11-25 17:36

>>13
yes

Name: Anonymous 2006-11-25 18:35

And since 0/0 = i, we can assume √-1 is both 0/0 and -0/0

Name: Anonymous 2006-11-27 3:43

lol it WAS 7815

Name: Anonymous 2006-11-27 6:18

>>16

Doesn't stop it from being a crappily worded question.

Anyone worth their salt can challenge this question, and win, if it showed up on anything remotely important.

Name: Anonymous 2006-11-27 8:28

if it showed up on anything remotely important
...you'd laugh, and ask "Who the hell made this up? A twelve year old?"

Don't change these.
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