4 digit passcode (note the date is European format, D/M/Y)
First digit is the square root of my birthday, 9 January, divided by three plus six.
Second digit is four plus seven minus the the sq. root of my b-day
Third digit is square root of b-day + actual date of D-day
Last is the 3rd digit minus the 2nd one.
Name:
Anonymous2006-11-22 21:36
7891
Name:
Anonymous2006-11-22 21:39
...wtf?
I tried didn't work, apparently the hint was:
Perhaps 1 was the third digit, while 2 was added onto the fourth digit...
Name:
Anonymous2006-11-22 21:47
3rd Digit. 3+9 = 12
How'd you end up with 9
Name:
Anonymous2006-11-22 21:59
i used the actual date of d-day, june 6, 1944
Name:
Anonymous2006-11-22 22:02
Oops, I meant B-day. I mistyped that
Name:
Anonymous2006-11-22 22:16
>>6
but yes i noticed 12 is not a one digit number, and if its < 8 then the fourth digit is negative. these instructions are not clear.
Name:
Anonymous2006-11-22 22:30
The instructions, word for word:
Now it's the square root of my birthday (9th of January), divided by three, add six. The second digit is four plus seven minus the square root of my birthday. The third digit it the square root of my birthday, plus the actual date of my birthday, the 9th. The final digit is the third digit minus the second digit.
Name:
Anonymous2006-11-23 0:28
Um? How is digit 3 supposed to be one?
Name:
Anonymous2006-11-23 0:29
W00t - last clue I got says that negatives WILL be result
Name:
Anonymous2006-11-23 4:21
First digit: Sq.rt.9 = 3/3 = 1+6 = 7
Digit two: 4+7=11 - 3 = 8
Digit three: 1? What? according to the clue, right?
Digit 4: = -7? Since negatives are accepted, added 2 is -5?
so, 7815?
Name:
Anonymous2006-11-24 17:03
You guys aren't taking into consideration that there are two equally correct answers to a square root problem.
Square root of 9 is (3, -3)
3^2 = 9
-3^2 = 9
As is, the question doesn't give you enough information to really get a definative answer, unless you want to go through trial and error and plug in 3 and -3 in all the spots it asks for a square root... and maybe get a few possible answers.
Its, imo, a shitty question for being vague about its instructions.