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Solving Rational Expressions - RQD HALP

Name: Anonymous 2006-11-21 2:24

Hay /sci/.

I've been trying to do this question for well over 2 hours. My friends have tried to help me, but I rejected them, believing I could do it myself. I do realize that the majority of users here are of a college/university math level...so I hope you can understand that we were all once fucking confused and help me out here.

Solve.

x+2 / x-1 + x-4 / x+2 =  x+1/x-1 + 1/2

I have the answer, but I don't know how to solve it. Thanks.

Name: Anonymous 2006-11-21 2:42

Whoops, tis

(x+2/x-1) + (x-4/x+2) = (x+1/x-1) + (1/2)

Name: Anonymous 2006-11-21 2:57

First, multiply both sides by the common denominator (x-1)(x+2):
(x+2)(x+2) + (x-4)(x-1) = (x+1)(x+2) + 1/2*(x+2)(x-1)

Expand everything:
x^2 + 4x + 4 + x^2 - 5x + 4 = x^2 + 3x + 2 + 1/2 * (x^2 + x - 2)

Multiply by 2 and do some simplification:
4x^2 - 2x + 16 = 3x^2 + 7x + 2

Put everything on one side:
x^2 - 9x + 14 = 0

Factor:
(x-2)(x-7) = 0

x = 2 or 7

Name: Anonymous 2006-11-21 3:35

Oh my gosh. Thank you so much.

Name: Anonymous 2006-11-21 11:59

>>1,2
Please learn how to use brackets properly.

Name: Anonymous 2006-11-21 12:03

>>5
learn how to be not so retarded kthx

Name: Anonymous 2006-11-21 13:11 (sage)

>>6
???

Name: Anonymous 2006-11-21 13:16

>>7
It was pretty obvious what he meant, so you don't have to pretend to not be able to read it okay.

Name: Anonymous 2006-11-21 16:02 (sage)

>>8
Well, I saw >>1 and thought he must've forgot to put brackets around the spaced apart thingies. Then I saw >>2 and I was confused, because it seemed to imply the lack of brackets was intentional since
(x+2/x-1) + (x-4/x+2) == x+2 / x-1 + x-4 / x+2
but
(x+2/x-1) + (x-4/x+2) != (x+2)/(x-1) + (x-4)/(x+2).

And now I'm retarded? Just learn how to use the notation properly, kthx.

Name: 4tran 2006-11-24 1:11

>>9
(x+2/x-1)==(x+2)/(x-1) almost always, but the former is not "proper math notation", though often used anyway so the place doesn't get clutterred by parentheses.

(x+2/x-1)==x+(2/x)-1 is rare (though technically correct "math notation"), and generally bad style

Name: Anonymous 2006-11-24 2:17

>>10
I don't know what country you're from, but over here (x+2/x-1) is always x+(2/x)-1. We call it 'precedence' and it makes equations unambiguous.

Name: 4tran 2006-11-24 4:56

I know of such a thing as precedence, but my point is that on the internet/other medium that involves typing, sometimes common sense > precdence

Name: Anonymous 2006-11-24 5:05 (sage)

>>12
Common sense is not leaving out the brackets where it's not allowed, goddammit.

Name: Anonymous 2006-11-24 9:49

>>13
dangnabit

fixed

Name: Anonymous 2006-11-25 18:42

Common sense? In Maths notation? Where?

f^-1 is the inverse function of f lol lol see it's -1 lol irony
...but sin^-1 is csc, gotcha!

sin is a function
...but since we like it a lot we omit parenthesis lol lol sin x

We're to lazy to write a dot for multiplication; can you imagine how tiring could that be?
...so when you say asinx you mean a · sin(x)... or was it arcsin(x)? Oh, wait, I think it means a·s·i·n·x... oh shi-

Name: Anonymous 2006-11-25 19:35

ive never seen anyone refer to csc(x) as sin^-1(x), sometimes sin(x)^-1, which is consistent and makes sense.

f^-1(x) != f(x)^-1
theyre two separate concepts, if you see them used interchangably its because whoever is presenting them doesn't understand what the notation means.

i agree that writing sin x is being loose though, and most teachers who pay attention will use parentheses because they recognize that it is a function.

to illustrate the inequality
suppose f(x) = x + 3
f^-1(x) = x - 3
satisfies f^-1(f(x)) = x

f(x)^1 = 1/(x+3)
satisfies f(x)*(f(x)^-1) = 1

Name: Anonymous 2006-11-26 5:02

>>15

that's why the inverse of sin is referred to as arcsin you noob.

Name: Anonymous 2006-11-26 7:42

>>1
x+2 / x-1 + x-4 / x+2 =  x+1/x-1 + 1/2=(((((((x+2) / x)-1) + x)-4) / x)+2) =  (((((x+1)/x)-1) + 1)/2)

Name: Anonymous 2006-11-26 9:53

>>16
f^-1(x) != f(x)^-1
That's what I'd hope, but maths teachers will omit the parenthesis for well-known functions such as sin, cos, tan, etc., and so, when they need to do sin(x)², they write sin²x (because it'd otherwise be confused with sin(x²)). Then they use csc to avoid writing sin^-1, but see what I mean.

>>17
Are you saying it's a "special case"? Proper syntax must not have "special cases".

Maths notation was designed by Larry Wall.

Name: Anonymous 2006-11-26 10:05

>>19
Math syntax is not meant to be read by a computer you stupid retard.

Name: Anonymous 2006-11-26 10:50

>>19
This is not a case of intelligent design, the notation has evolved over thousands of years. There's bound to be some weirdness to it.

Still, consciously introducing ambiguity cannot be justified.

Name: Anonymous 2006-11-26 15:21

>>20

uh, why not?

Math syntax follows a set list of rules... which is what a computer does all day long.

If your computer isn't understanding your attempts at feeding it a math problem, either you lack the necessary software or you're inputting it wrong.

Either way, you're the retard.

Name: Anonymous 2006-11-26 15:26

>>1-21
1*0=0=2*0
1=2

Name: Anonymous 2006-11-26 15:28

>>22
(-1)^0.5=1/0

Name: 4tran 2006-11-26 18:07

>>21
I justify introducing ambiguity with laziness.  In most such cases of ambiguity, it's almost always obvious what is meant.

8^1/3 = 2; that's the most obvious way

Strict math notation states that the exponent is to be evaluated first, yielding 8/3.

It's a pain having to write 8^(1/3) every time you need to mention an exponent.

Name: Anonymous 2006-11-26 19:37 (sage)

It's no more of a pain than, say, writing 'you' instead of 'u'.

Don't change these.
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