Does 2.9999... equal 3?
1
Name:
Anonymous
2006-08-07 7:12
I think this is an important question deserving of this bulletin board.
2
Name:
Anonymous
2006-08-07 7:30
Yes Anonymous you are correct in non-standard analysis 2.999... and 3 are distinct numbers with the difference being an element of the hyperreals.
3
Name:
Anonymous
2006-08-07 10:38
a what??
4
Name:
Anonymous 2006-08-07 11:19
(sage)
old topic. gtfo.
5
Name:
Anonymous 2006-08-07 20:08
(sage)
kill it with sage
6
Name:
Anonymous
2008-01-05 23:25
Hyperreals, yes.
7
Name:
Anonymous 2008-01-06 2:27
8
Name:
Anonymous
2008-01-06 3:09
Your troll-fu is weak, little earwig.
9
Name:
Anonymous
2008-01-06 3:14
We're no strangers to looove
10
Name:
sage 2008-01-06 10:23
sage
11
Name:
Anonymous 2008-01-06 20:44
>>1
no, it equals 2.9999..... dumbass
12
Name:
Anonymous
2008-01-19 14:02
Honestly, I hate it when people talk about this crap, and I think the guy that thought of this is an idiot. It's a lot easier just to work with 3 (or two, or one....).
13
Name:
Anonymous
2008-01-19 17:11
>>11
2.999999999999999...=1
14
Name:
Anonymous
2008-01-20 5:08
15
Name:
Anonymous 2008-01-21 14:17
2.999... = 3 - 0.000...1
16
Name:
Anonymous
2008-01-22 4:40
algebra
17
Name:
Anonymous 2008-01-22 14:30
18
Name:
Anonymous 2008-01-24 13:00
2.999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999999=sage
19
Name:
Anonymous
2008-09-08 5:35
2.9999999999 ~ 3