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e^(i(pi)) = -1

Name: Anonymous 2006-03-07 17:52

discuss

Name: Anonymous 2006-03-09 11:21

>>8

You're an idiot. You can't rearrage the terms of an infinite sum where the signs of the term alternate. gb2/maths/

tip: for any real number L and any alterating series, you can rearrage the terms in the series so that the series converges to L.
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