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e^(i(pi)) = -1

Name: Anonymous 2006-03-07 17:52

discuss

Name: Anonymous 2006-03-09 11:16

>>7
That's not what I meant and you know it.
Maths relies on axioms anyway, but at a lower level.
What I assumed is that people knew how to derive
e^(i(X) = cos(X) + i * sin(X) from a fucking taylor series. Do you need me to explain how to do that, or do you need to take a year 11 maths course all over again?

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