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1 + 1 = 3

Name: Anonymous 2006-03-06 1:26

Discuss.

Name: Anonymous 2006-04-04 16:03

>>40

ln(1), you know what it is, motherfucker?

Name: Anonymous 2006-04-04 16:04

Some people have no sense of humor...

Name: Anonymous 2006-04-04 17:47

>>42
Nobody wants that kind of humor

Name: Anonymous 2006-04-04 21:07

>>41
ln(1) is the power to which e would need to be represented in order to equal 1.
but
log base sqrt(1) of 1, i.e. the power to which sqrt(1) would need to be represented in order to equal 1, would be defined and not 0, and you can use any base log for that division.

Name: Anonymous 2006-04-04 22:51 (sage)

>>19

.999+1.111=2.11 not 2.111

.999+1.001=2

Plus, if 2 = 0 and 1 > 0 then 1 > 2 which is broken...

Have fun here...

Name: the pope 2006-04-05 1:56

if 1+1=3, then I am the pope.

Name: Anonymous 2006-04-05 2:49

>>44

yeah so you have

thus ln(1)/ln(1) = 2

thus ln(1)/ln(1) = 3

which gives you the expressions 0/0 which are not allowed.

Name: Anonymous 2006-04-05 2:51

>>44

also for any non zero real number x. x^y = 1 iff y = 0.
sqrt(1) is a non zero number, so
>would be defined and not 0
is clearly false.

Name: Anonymous 2006-04-05 12:01

Trolling /sci people with intentionally flawed logic, misconceptions and nonsense is hilarious.

Name: Mathonymous 2006-04-06 11:54

1,9999+1,1111=3
1,999+1,111=3
1,99+1,11=3
1,9+1,1=3
1(2)+1=3
........../lol

Name: Anonymous 2006-04-06 12:04

>>50
Incorrect numbering. it is meant to be 1.999... and 1.111...
the '...' represent the endless number series

Name: Anonymous 2006-04-06 18:17

Let A be an algebra where:
1 and 3 are constant symbols
+ is a binop symbol
1+1=3 is an axiom

An infinite number of such algebras can be constructed.

Name: Anonymous 2006-04-07 3:59

>>52
Yes, they can, but to anyone but the maker of the algebra would see it as gibberish and the effort would be moot.
If 1 + 1 = 3 then 1 = 1.5, and since 1 = 1, then 1 != 1.5. Therefore, 1 + 1 != 3

Name: Anonymous 2006-04-07 5:04

1=0, 0=1, there is no 2, without 2 there is no 3

Name: Anonymous 2006-04-07 6:42

but 1 obviously does not = 0, because 1 is something, and 0 is nothing

Name: Anonymous 2006-04-07 7:55

>>53
You fail at universal algebra. Badly.

Name: Anonymous 2006-04-07 10:27

>>53
he's saying something like, pretend 3 is the new 2, and 2 is the new three,
1 + 3 = 2
1 + 2 = 4
3 + 2 = 5
he's just pointing out the only way to really ever prove 1 = 2 would require changing the way we intepret the numbers.

Name: Anonymous 2006-04-07 12:26

it's called proof by contradiction, by making a stupid assumption, and showing how stupid the assumption is, therfore falsifying it.

Name: Anonymous 2006-04-07 14:23

>>14

1.99999999=2 dumbass

Name: Anonymous 2006-04-07 15:18

Dumbasses? In my world4ch?

Name: Anonymous 2006-04-14 11:19

1+1((+1)hidden)=3

Name: Anonymous 2006-04-14 19:54

Should I get my math teacher up in hurr?

Name: Anonymous 2006-04-15 7:33

Yes, but he will say this is correct because he has tenure. 

Name: Anonymous 2006-04-15 7:49

NINTENDO 64 GET

Name: Emperor 2006-04-15 8:21

What do you think?

Name: Anonymous 2006-04-15 8:56

公理
・先頭元0が存在する。
・任意の自然数aにはその後者suc(a)が存在する。

定義
suc(0)=1;suc(1)=suc(suc(a))=2
定理
suc(a)+b=a+suc(b)=suc(a+b)
証明
suc(1)=1+1.
また、1=suc(0)
∴suc(suc(0))=2
∴1+1=2 QED

Name: Anonymous 2006-04-15 11:11

>>66
all i see r lots of squares o_o

Name: Anonymous 2006-04-16 1:23

>>67

You don't have the "vision".

Name: Anonymous 2006-04-16 6:00

みんな日本語ではなそうよ

Name: Anonymous 2006-04-16 6:42

>>15
Your use of sets is clearly flawed.
You haven't studied the great fluicity of calculus where if
a fuction is in a specific set of numbers there is a limit to which this function gets close to a number outside of it's own set and thus since numbers are themselfs functions of information it is not flawed that the a number cannot achive a number outside of it sets and even if two numbers of the same function in the same number set cannot achive a number outside of it's set. Thus, you should study the physics of how numbers can formulate in this real plane that we live in.

Name: Anonymous 2006-04-25 1:37

         ∧_∧   ┌────────────
       ◯( ´∀` )◯ < 1 + 1 = 3
        \    /  └────────────
       _/ __ \_
      (_/   \_)
           lll 

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