Name: Anonymous 2013-10-21 23:51
Define a procedure that takes three numbers as arguments and returns the sum of the squares of the two larger numbers.
import anus
#define LARGE1(x, y, z) ((x) > (y) ? (y) > (z) ? (x) : (x) > (z) ? (x) : (z) : (y) > (z) ? (y) : (z))
#define LARGE2(a, x, y, z) ((a) == (x) ? (y) > (z) ? (y) : (z) : (a) == (y) ? (x) > (z) ? (x) : (z) : (x) > (y) ? (x) : (y))
#define SUMSQ(x, y) ((x * x) + (y * y))
double someKidsHomework(double x, double y, double z)
{
int lg = LARGE1(x, y, z);
return SUMSQ(lg, LARGE2(lg, x, y, z));
}
function sumofsquaresoftwolargest(x,y,z){
var t = [x,y,z];
t.sort();
var u1 = t[1]; var u2 = t[2];
return u1*u1 + u2*u2;
}[@]$2>{2?}%~+