Nikita: the latest news

Nikita expands his internet presence by attacking the Russian functional programming community: http://ru-declarative.livejournal.com/108182.html

Cute!

>>177

So you want a function f: R -> R such that:

for all a,b in R, f(a + b) = f(a) + f(b)
for all a,c in R, f(ac) = f(a)f(c)

and then 0 and 1 are fixed?

Is that it? I'm not that great in ring theory.