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Why is c++ weird?

Name: Eamon 2012-08-28 19:39

Why is this line ok:

long double x = (1 / sqrt(2));

but this one isn't:

long double x = (1 / 4);

?

Name: Anonymous 2012-08-28 20:15

why don't you go and learn c++?

Name: Anonymous 2012-08-28 20:48

Because one is a floating point type and the other one is an integral type.

Name: Anonymous 2012-08-29 0:01

Both of them are ok.

Name: SEPPLES 2012-08-29 2:27

SEPPPLES

Name: PROUD OF SEPPLES 2012-08-29 13:16

enum AnimalFlags
{
    HasClaws = 1,
    CanFly =2,
    EatsFish = 4,
    Endangered = 8
};

AnimalFlags seahawk = CanFly | EatsFish | Endangered; // error
AnimalFlags seahawk = static_cast<AnimalFlags>(static_cast<int>(CanFly) | static_cast<int>(EatsFish) | static_case(Endangered)); // ok

Name: Anonymous 2012-08-29 15:46

long double x = (1 / 4);

This an integer division.
You must have at least one value which is not an integer.
Like this:
long double x = (1 / 4.0);

http://cnx.org/content/m18717/latest/

Name: Anonymous 2012-08-29 17:43

HOLY SHIT OP ORDER OF EVALUATION MOTHERFUCKER HAVE YOU HEARD IT IT"S EXPLAINED IN LITERALLY THE FIRST SECTION OF SICP MOTHERFUCKER HAVE YOU READ IT TODAY

Name: Anonymous 2012-08-30 15:53

C++ is better than xsl, holy shit look at this ugly motherfucker http://nltk.org/nltk_data/index.xsl

Name: Anonymous 2012-08-30 17:29

>>6
Just use enum classes

Name: Anonymous 2012-08-31 7:04

>>10
I actually believe that's the case why WinAPI headers still have thousands of #defines instead of enums.

Name: Anonymous 2012-08-31 7:48

>>10,11
enums are for enumerating things, not defining arbitrary constants.

Name: Anonymous 2012-08-31 9:08

>>12
Seriously? And what are WM_ messages, hundreds of arbitrary constants?

Name: Anonymous 2012-08-31 9:32

>>13
Using enum for information interchange is bad style because it's not as explicit as #define. C++ is shit.

Name: Anonymous 2012-08-31 10:23

>>14
Come back when you learn SEE.

Name: Anonymous 2012-08-31 10:36

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Name: Anonymous 2012-08-31 10:46

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Name: Anonymous 2012-08-31 10:48

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Name: Anonymous 2012-08-31 13:56

C++ has type inference. It infers that sqrt returns a double so the whole expression is a double. The other one is an integer division because the compiler infers that both operands are int.

Name: Anonymous 2012-08-31 16:21

>>22
double sqrt(double);
Nice type inference.

Name: Anonymous 2012-08-31 16:24

>>23
how about template <class=T> T sqrt(T)?

Name: Anonymous 2012-08-31 16:48

>>24
Well, I wouldn't call that type inference:

template <typename TOut, typename TIn>
TOut round(TIn v) {
   return (TOut)(v + 0.5);
}

int i = round(1.54); //error: no matching function for call to ‘round(double)’

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