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drunk programming

Name: Anonymous 2012-04-16 20:32

do you?

how efficient are you?

how legible is your code?

do you remember what you intended to do the next day?

Name: Anonymous 2012-04-17 9:15

>>7
Your solution works, but only because you're lucky.
maximum $ filter (\x -> let s = show x in s == reverse s) [x*y | x <- [100..999], y <- [100..999]]

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drunk programming

1 Name: Anonymous 2012-04-16 20:32

10 Name: Anonymous 2012-04-17 9:15

Name: Anonymous 2012-04-16 20:32

Name: Anonymous 2012-04-17 9:15