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/PROG/RIDERS UNITE

Name: Anonymous 2012-04-08 3:40


Hello /prog/

if i have:

n = a^b
m = b^c

Then how can i take n and m and figure out what b is?

Name: Anonymous 2012-04-08 3:40


fix: (not and)
n = a or b
m = b or c

Name: Anonymous 2012-04-08 3:42

wtf are you are trying to do?

Name: Anonymous 2012-04-08 3:43

this sounds like homework

Name: Anonymous 2012-04-08 3:45

>>3
trying to crack something that uses a simple algorithm:


char *str = "prog";
char[4] newstr;

newstr[0] = str[0]^str[1];
newstr[1] = str[1]^str[2];
newstr[2] = str[2]^str[3];
newstr[3] = str[3]^str[0];

Name: Anonymous 2012-04-08 6:36

For starters you forgot to add room for your null terminator for newstr.

Name: Anonymous 2012-04-08 6:50

>>5

You can do it.


a ^ 0 = a
a ^ a = 0
a ^ b = b ^ a
(a ^ b) ^ c = a ^ (b ^ c)

Name: Anonymous 2012-04-08 7:08

>>2
^ isn't and, it's xor.

Name: Anonymous 2012-04-08 7:15

You can't.

Name: Anonymous 2012-04-08 10:55

NP-ROCK HARD DICK

Name: <---- Check em 2012-04-08 11:12

dubz

Name: Anonymous 2012-04-08 13:36

>>8
⊕ is xor sir

Name: Anonymous 2012-04-08 17:28

You can definitely do it is you know at least one byte of the original string. So that means you can take it down to 256 possibilities in general. If the string is long enough and if you know what it should look like, then you can easily pick the logical one.

Name: bampu pantsu 2012-05-29 4:15

bampu pantsu
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