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A solution to an undergrad math problem

Name: Anonymous 2011-09-02 18:54

I'm forced to take a set theory....

The homework question: Find two sets A and B such that A is a member of B and A is a subset of B. I talked to my classmates and all the answers seemed a bit strange. The most common answer seemed to be A = {} and B = {{}}. That doesn't really seem right. So here is what I came up with...

A = {7}
B = {{7}, 5, 7}

A is a member of B since {7} is in B.
A is a subset of B since 7 is in B.

Name: Anonymous 2011-09-02 19:05

A and B are both the universal set.

Name: Anonymous 2011-09-02 19:33

You must revolt against the Jews.

Name: Anonymous 2011-09-02 21:22

A = {} and B = {{}} is correct.

Clearly A is a member of B (A is the empty set, and B is a set containing the empty set).

A is also a subset of B, because the empty set is automatically a subset of any set.

Your answer is also correct.

Name: Anonymous 2011-09-02 21:28

A is a member of B forces B = {A,other,stuff,here}

A is a subset of B forces something like A = {other,here}

So (A,B) = ({other,here},{{other,here},other,stuff,here}) would work.

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question is, can you have A = {A,other,here}?

Name: Anonymous 2011-09-02 22:16

>>4
Thanks.

Name: Anonymous 2011-09-02 22:47

You're a fucking moron and you're going to fail, you're too stupid for mathematics, try taking up a job at macdonalds or something.

Name: Anonymous 2011-09-03 2:13

You're a fucking genius and you're going to succeed, you're too smart for macdonalds, try taking up a job in mathematics or something.

Name: Anonymous 2011-09-03 9:49

Wouldn't two sets with the same contents satisfy the solution?

Name: Anonymous 2011-09-03 9:55

>>9
No you fucking retard, how can you morons fail at this easy shit?

Don't change these.
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