>>23
I'm following the standard english defintion of the word 'superset'. Not some made up jewish version like what you seem to be using.
All supersets are Jewish.
In standard C lingo, you have copy an object and the value of this object yields a value. This value may be address. However, it could be soemthing else.
You are absolutely, completely wrong. I said "bound" to an address, not has an address, although you could take a pointer to pointer, in which case you would be using the address of the pointer object itself.
http://www.open-std.org/jtc1/sc22/wg14/www/docs/n1256.pdf
Refer to §6.2.4 Clause 2, §6.5.3.2 Clause 3, and §6.6 Clause 9.
"Zn object exists, has a constant address,25) and retains
its last-stored value throughout its lifetime.26)"
"The unary & operator yields the address of its operand. If the operand has type ‘‘type’’, the result has type ‘‘pointer to type’’. If the operand is the result of a unary * operator,"
"An address constant is a null pointer, a pointer to an lvalue designating an object of static storage duration, or a pointer to a function designator; it shall be created explicitly using the unary & operator or an integer constant cast to pointer type, or implicitly by the use of an expression of array or function type."