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Save my C++

Name: A times B equals F 2011-02-03 9:51

Why doesn't this work? ='[

//Set up nested loops:
    for(int i = 0; i < 3; ++i)
    {
        for(int j = 0; j < 3; ++j)
        {
            //Multiply elements of A * B = C:
            C[j] = A[i] * B[j];

            //Deal with Carry of multiplication:
            if(C[j] > 9)
                C[j+1] += CarryTheOne( C[j] );

            //Add to contiguous answer:
            F[j+i] += C[j];

            //Deal with Carry of addition:
            F[j+i+1] += CarryTheOne( F[j+i] );
        }

}
//--------------------------

int CarryTheOne( int & x )
{
    if(x > 9)
    {
        //get unit element ( < 9 )
        x -= 10;
        //return carry (only ever 1)
        return 1;
    }
    return 0;
}

Name: Anonymous 2011-02-03 9:53

C++
It doesn't work.

Name: Anonymous 2011-02-03 9:58

When i input 62 & 123 (well 26 & 321) i get 6526 (well 6256) instead of 7626 (well 6267)

Name: Anonymous 2011-02-03 10:00

>>3
I don't see any [code] tag.

Name: Anonymous 2011-02-03 11:42

>>1
My first guess would be the lack of [code] tags.

Name: Anonymous 2011-02-03 13:23

>>3
Well, shut the fuck up.

Name: TrEy 2012-03-17 4:03

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Name: Anonymous 2012-03-17 5:36

because you are an idiot, can't even understand algorithms that are used by 7 years olds.

carry can be greater than 1.

Name: Anonymous 2012-03-17 6:53

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Name: kodak_gallery_programmer !!kCq+A64Losi56ze 2012-03-17 8:21

Someone needs to retake a data structures class.

Name: Anonymous 2012-03-17 9:19

Save my dubs.

Name: Anonymous 2012-03-17 10:09

>>1

The first section of code isn't in any kind of function. It's just floating there.

Name: Anonymous 2012-03-17 10:26

CarryTheOne needs a int*.
C[j] is an int. Try calling CarryTheOne with C+j instead.

Don't change these.
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