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[C] Comparisons versus XOR

Name: Anonymous 2010-11-14 12:39

You're parsing arguments and they are mutually exclusive.


if ((A == 0 && B == 0) || (A != 0 && B!= 0))
 return EXIT_FAILURE;

 versus


if ((A ^ B) == 0)
 return EXIT_FAILURE;

Name: Anonymous 2010-11-14 12:45

versus

if(A/B == 0)
 return EXIT_FAILURE;

Name: Anonymous 2010-11-14 12:50

#include "void.h" //handles all the common functions,#defines,#ifdefs and #includes
unless(A^B)return EF;

Name: Anonymous 2010-11-14 12:50


if(!(A && B) && !(!A && !B))
    return ANUS_FAILURE;

Name: VIPPER 2010-11-14 12:53

>>1
You might aswell use:

if ((!A && !B) || (A && B))
 return EXIT_FAILURE;

if (!A ^ B)
 return EXIT_FAILURE;

Name: Anonymous 2010-11-14 12:54

if(!(A && B) && !(!A && !B))
    return ANUS_FAILURE;

Name: Anonymous 2010-11-14 12:55

>>5
if (!A ^ B)
Logical NOT used in bitwise operation

Name: Anonymous 2010-11-14 12:57

>>4 Oops!
if(!(!(A && B) && !(!A && !B)))
    return ANUS_FAILURE;

Name: Anonymous 2010-11-14 15:27

>>5
aswell
Faggot.

Name: Anonymous 2010-11-14 15:33

Short-circuits are faster if we are dealing with booleans. If A and B are HUGE-bit extreme floats it is not cool to wake your x87.

Name: Anonymous 2010-11-14 21:39

One's anus should not use xor in this place. Consider A = 2, B=4

First version will return, xor version will not.
ENTERPRISE solution:

if(!!a  == !!b) return;
Using See !! Normalise Integer operator.
And real hardcore

if((!!a + !!b)&1==0) return;

Name: Anonymous 2010-11-15 2:09

if (!A ^ !B) return EXIT_FAILURE;

Name: Anonymous 2010-11-15 14:44


#include <stdio.h>
#include <stdlib.h>

int main(void)
{
auto const unsigned int A = 2;
auto const unsigned int B = 4;
 if ((A == 0 && B == 0) || (A != 0 && B!= 0))
  printf("test01\n");
 if ((A ^ B) == 0)
  printf("test02\n");
 if (A/B == 0)
  printf("test03\n");
 if (!(!(A && B) && !(!A && !B)))
  printf("test04\n");
 if ((!A && !B) || (A && B))
  printf("test05\n");
 if (!A ^ B)
  printf("test06\n");
 if (!(A && B) && !(!A && !B))
  printf("test07\n");
 if (!!A  == !!B)
  printf("test08\n");
 if ((!!A + !!B) & 1 == 0)
  printf("test09\n");
 if (!A ^ !B)
  printf("test10\n");
 return EXIT_SUCCESS;
}

Output:
test01
test03
test04
test05
test06
test08

Name: Anonymous 2010-11-15 17:07

Can I ask what is going on here? What was op trying to say? Two mutually exclusive parameters? As in... not equal?

like... != ?
!(A ^ B) === A != B

But the two propositions are not equivalent so how is it a comparison?
I am confuse.

Name: Anonymous 2010-11-15 21:37

I'd just like to inform y'all that PHP, king of languages, has a logical xor operator. Enjoy your portable assembly.

Name: Anonymous 2010-11-16 2:17

if ((!!A + !!B) & 1 == 0)
no test 9

Fuck! I forgot that C has shittiest precedence.

if ((!!A + !!B) & 1 == 0)printf("hurr\n");
if (((!!A + !!B) & 1) == 0)printf("durr\n");

Output:
durr

IHBT by K&R.

Name: Anonymous 2010-11-16 21:12

>>14
From the first example given by the OP you should be able to get that he's parsing two arguments and only one is accepted into his shit.

Name: Anonymous 2010-11-16 22:24

xor :: Bool -> Bool -> Bool
xor True = not
xor False = id

Name: Anonymous 2010-11-17 0:31

>>17
but... Oh did op not realize second example wouldn't work?

... ooooo k.

Name: Anonymous 2010-11-17 1:27

but... Oh did >>19 realize he have bitch tits?

... ooooo k.

Name: Anonymous 2011-02-03 2:29

Name: Anonymous 2011-02-17 20:29

that's cool and all, but check my doubles over there<
Don't change these.
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