You should be able to solve this
Name:
Anonymous
2010-06-15 4:34
i = 0; i += i++ + ++i + i--
Name:
Anonymous
2010-06-15 4:41
There's no semicolon at the end so it gives an error.
Name:
Anonymous
2010-06-15 4:57
The answer is 2.
Name:
Anonymous
2010-06-15 8:26
implementation dependant, I'd have thought
Name:
Anonymous
2010-06-15 12:33
hard mode:
++i += i++ + ++i + i-- + --i
Name:
Anonymous
2010-06-15 12:43
dependant
misuse of sage
sure is toddlers in here
Name:
Anonymous
2010-06-15 12:51
>>6
Incidentally, your post was also a misuse of sage. In that you forgot to use it.
Name:
Anonymous
2010-06-15 12:53
>>3
<script language="javascript">
var i = 0;
document.write(i + " ");
i += i++;
document.write(i + " ");
i += ++i;
document.write(i + " ");
i += i--;
document.write(i + " ");
i = 0;
i += i++ + ++i + i--;
document.write(" -> " + i);
</script>
0 0 1 2 -> 4
Name:
Anonymous
2010-06-15 13:39
>>1
Undefined in C, compile error in any non-retarded modern language.
Name:
Anonymous
2010-06-15 13:49
i+=i+++++i
Name:
Anonymous
2010-06-15 14:04
int i = 5;
while (i --> 0)
printf("%d\n", i);
The --> operator!
Name:
Anonymous
2010-06-15 15:07
a->b-->c<---d
VALID C CODE
Name:
Anonymous
2010-06-15 15:15
>>12
If by ``
VALID'' you mean ``
INVALID''.
Name:
Anonymous
2010-06-15 15:16
>>13
If by ``
INVALID'' you mean ``
WRITTEN BY AN %s''
Name:
Anonymous
2010-06-15 17:08
Perl says 5
Name:
Anonymous
2010-06-15 17:37
Javascript says 4.
Name:
Anonymous
2010-06-15 18:00
Guido says SyntaxError™.
Name:
4
2010-06-15 18:45
Name:
Anonymous
2011-01-31 20:37
<-- check em dubz