C programming

#include <stdio.h>
/* count digits, white space, others */
main()
{
int c, i, nwhite, nother;
int ndigit[10];
nwhite = nother = 0;
for (i = 0; i < 10; ++i)
ndigit[i] = 0;
while ((c = getchar()) != EOF)
if (c >= '0' && c <= '9')
++ndigit[c-'0'];
else if (c == ' ' || c == '\n' || c == '\t')
++nwhite;
else
++nother;
printf("digits =");
for (i = 0; i < 10; ++i)
printf(" %d", ndigit[i]);
printf(", white space = %d, other = %d\n",
nwhite, nother);
}

Why is it, on line 12, ++ndigit[c-'0']; is used instead of just ++ndigit[c];?

Because ASCII values 0-9 are NUL, SOH, STX, ETX, EOT, ENQ, ACK, BEL, BS and HT.

cool indentation
The ASCII code for 0 is 48 I believe and all the other numbers are after that.
So if c is say '8' that expression would be 56 - 48 which is 8, the position you want.

Because if c is a character, the '0' character represents the number 48, '1' = 49, etc. Since the array is only size 10, accessing index 48 would be an out of bounds reference. By subtracting '0', you reduce the range to 0-9, which are the fight indices.

Alright. Thanks muchly.

WE HELPED HIM!!!

>>6
Yes, and we should all be ashamed of it.

wchar_t

>>8
WIDE CHARACTER MY ANUS

>>9
FUCK OFF SPAMMER

Use SPACE
USE EMPTY LINES
Use BRACKETS!
BRACKETS ARE COOL!
NOT USING THEM MAKES YOU UNCOOL!

MAKE IT INT Main(int argc, char argv[]) AND RETURN 0 AT THET END STATNG THAT YOUR PROGRAM WAS A SUCCESS!

NOT DOING SO WILL RESULT IN PISS-POOR PROGRAMMING!

IF YOU ARE A COMPUTER GEEK YOU WOULD WANT TO BE POPULAR AT LEAST WITH THE GEEKS RIGHT?

THE FIRST FOR LOOP IS UNNECESSARY USE
int ndigit[10] = {0};

c IS NOT AN INT USE CHAR!!!

NO NEWLINE NEED INSIDE OF AN PRINTF!
IF YOU NEED ONE CLOSE PRINTF AND START WWITH ANOTHER PRINTF WHERE YOU LEFT OFF!!!

AND MOST IMPORTANTLY DO YOUR HOMEWORK YOURSELF!!!!

>>10
SPAM MY ANUS

>>11
c IS NOT AN INT USE CHAR!!!
lrn2c
IHBT