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Haskell point-free

Name: Anonymous 2009-12-25 17:12

I have this:


ops :: [[Char] -> [Char]]
...
fun :: [Char] -> [[Char]]
fun str = zipWith ($) ops $ words str


How do I write fun in a point-free style? Dropping the argument gives me type errors.

Name: Anonymous 2009-12-26 2:03

>>2
So fun = zipWith id ops . words

Remember, any time you pass ($) to a function that expects another function, you can substitute id and it will still work

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