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Haskell point-free

Name: Anonymous 2009-12-25 17:12

I have this:


ops :: [[Char] -> [Char]]
...
fun :: [Char] -> [[Char]]
fun str = zipWith ($) ops $ words str


How do I write fun in a point-free style? Dropping the argument gives me type errors.

Name: Anonymous 2009-12-25 17:14

I mean, I got this;

fun = (zipWith ($) ops).words

But it's ugly with all these parens. Is there a cleaner way?

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