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I suck at Haskell :(

Name: Anonymous 2009-08-11 14:05



ints [1] -eval-> [1,2,3,4,5..]

ints [3] -eval-> [1,4,7,10,13..]

ints [1,2] -eval-> [1,2,4,5,7,8,10,11..]

ints [1,1,3] -eval-> [1,2,3,6,7,8,11..]

I hope you know what I mean. How do I write ints in terms of foldl/r and zipWith?

Name: Anonymous 2009-08-11 14:35

itym ints = scanl (+) 1.cycle

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