Return Styles: Pseud0ch, Terminal, Valhalla, NES, Geocities, Blue Moon. Entire thread

Have to learn something ;_;

Name: Anonymous 2009-02-18 14:40

Sup /prog/

I chose to do this game authoring course at college but I thought they were going to teach me how to code.
Turns out they're not despite it saying they would in the description.
I just want a language that's [fairly] easy and I can learn within 4 months. I also get the choice of DirectX or OpenGL and I don't know fuck about either of them but have been told DirectX is more retard-friendly.
So what language and opengl or directx?

Name: Anonymous 2009-02-18 15:01

http://msdn.microsoft.com/en-us/xna/aa937793.aspx

XNA: managed code (.net), works on PC/XBAWKS/Zune, free as in beer

enjoy not diddling around with internals

Name: Anonymous 2009-02-18 15:09

READ SICP!!!

Name: Anonymous 2009-02-18 15:42

>>2
This.  For hobby-level game design, XNA is about as good as you can get. (It uses DirectX.)

Also, DirectX is more friendly because Microsoft gives a lot of nice tools for it.

Name: =+=*=F=R=O=Z=E=N==V=O=I=D=*=+= 2009-02-18 15:42

Use your Cerebral Cortex to learn new things

Name: FROZENVOID MEME FAN 2009-02-18 15:44

>>5
You're not the real thing

Name: =+=*=F=R=O=Z=E=N==V=O=I=D=*=+= 2009-02-18 16:07

>>6
You're
You are

Name: Anonymous 2009-02-18 16:23

>>7
Your
fixed

Name: Anonymous 2009-02-19 0:02

everyone knows that sepples is designed for gaymans, learn that

Name: Anonymous 2009-02-19 0:07

I hope you're good at math for graphics programming...it's kinda required.

Also, go with OpenGL. It's open source!

Name: Anonymous 2009-02-19 1:07

learn haskell, then do stuff like this: http://muaddibspace.blogspot.com/2009/02/universes-for-discrimination-proofs.html

Name: !frozEnO.T6 2009-02-19 1:16

OpenGL is old and is not keeping with the times, and XNA/DirectX is bloatware.

Use OpenAL, it has all the advantages of free open development, but with better design and is much faster and more cutting edge.

Name: Anonymous 2009-02-19 2:04

>XNA/DirectX is bloatware

◔ヮ◔

Name: Anonymous 2009-02-19 2:05

>>12
2/10

Try harder next time!!

Name: Anonymous 2009-02-19 2:18

hello im directX the sdk join my community of developers if you payme enough i will give you access to a private area of 3d grafix ;)
http://msdn.microsoft.com/en-us/directx/default.aspx

Name: Anonymous 2009-02-19 5:50

>>1
I have heard the exact opposite about DirectX from my professor who has been doing 3D visualization for 20 years. If you're a beginner start with OpenGL in C. Everything you'll learn will easily translate to Direct3D because both D3D and OGL do the same thing. The concepts behind both are the same, it's just the APIs are different.

That and developing with OpenGL doesn't cost you anything.

Name: Anonymous 2009-02-19 6:00

>DirectX if...
>Otherwise...
>DirectX

Cool bro.

Name: FrozenVoid 2009-02-19 6:41

>>18
If A then A else A
What's so hard to understand?
I suggest you take a class in propositional logic and study what a ``tautology'' is.

Name: Anonymous 2009-02-19 6:42

>>19
What happened to you FV? You used to be funny, now I weep at your posts

Name: Anonymous 2009-02-19 7:58

>>22-23
lol
! and = are, like, 10 whole keys distant from each other

Name: Anonymous 2009-02-19 17:24

>>25
So you're retarded.

Name: Anonymous 2009-02-19 17:53

>>26
Says the man replying to an invisible post.

Name: Anonymous 2009-02-19 21:53

>>27

oh wow.. someone forgot about the script they installed.

Name: Anonymous 2009-02-19 22:32

>>28
？ I didn't forget, I just re-enabled it after being an idiot and replying to one of his posts.

Name: Anonymous 2009-02-20 4:00

Solve this bitch.
x = 1+1

Name: THE ANONYMOUS SAGE 2009-02-20 4:10

C with OpenGL.
XNA and DirectX are Micro$hit proprietary, and if you want to be taken seriously, you'll stop using Windows, and get a REAL operating system.

Name: Anonymous 2009-02-20 7:34

>>30
You're missing a ;

Name: Anonymous 2009-02-20 8:50

Solve this bitch.
x = 1+x

Name: Anonymous 2009-02-20 9:15

>>33
+/- infinity

Name: Anonymous 2009-02-20 9:34

>>33
x=1+x
multiply both sides by x: x2=x+x2
subtract x2 from both sides: 0=x

Name: Anonymous 2009-02-20 9:40

>>33
You raised the value of x by 1.

If this is part of a loop, it'll continue raising x by 1 for as long as possible.

As for what x is, it could be anything- The important thing is that after your line, it'll be 1 higher. But only if you don't forget to close it with a ;

Name: Anonymous 2009-02-20 10:21

>>33
You have not mentioned to what set X is supposed to belong to, as well as the definition of the '+' operation and from what set to what set does it operatate.

If x ∈ R, where '+' is the addition operation over R, then the solution set is Sx= ∅ and |Sx| = 0. In plain terms, there are no solutions.

Name: Anonymous 2009-02-20 10:23

>>37
s/operatate/operate//

Name: Anonymous 2009-02-20 10:24

>>35
Substitute to the original equation.
Receive fail.
Go back to middle school.
No profit.

Name: Anonymous 2009-02-20 10:32

>>35
If you wish to multiple your equation by a number, you can only do so if the number is not null, a fixed version of your ``proof'' is:
Equation:x=1+x

If x != 0, we can multiply both sides by x: x2 = x+x2

subtract x2 from both sides: 0=x, which contradicts our statement that x must not be 0. In the event, x = 0, we obtain 0=1 by substition, which means that the equation has no solutions.
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