lol unix

what is the output of this program?
#include <stdio.h>
#include <unistd.h>

int main(void){
 char *s[2] = {"a", "b"}, *d[2];
 d[0] = crypt(s[0], "xx");
 d[1] = crypt(s[1], "xx");
 printf("%s -> %s\n%s -> %s\n", s[0], d[0], s[1], d[1]);
 return 0;
}

a.c: In function ‘main’:
a.c:6: warning: implicit declaration of function ‘crypt’
a.c:6: warning: assignment makes pointer from integer without a cast
a.c:7: warning: assignment makes pointer from integer without a cast

>>2
#include <unistd.h>
http://www.opengroup.org/susv3xsh/crypt.html

lrn2POSIX

>>3
YHBT. YHL. HAND.

The return value of crypt() points to static data that is overwritten by each call.

>>3
>>2 is probably using some GNU shit that requires some gayass #define __FAGGOT_SOURCE beforehand.

>>6
What do you use other than GNU shit?

>>7
Just don't talk to them

>>7
ANONIX, duh.

Well, I warned you

>>9
Ssh! Super GNU, Defender of the GPL might hear you!

>>9
What?

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post by retard who thinks cryptography makes him elite programmer

Don't change these.

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