PHP HELP NEEDED

how can i manage to let someone logged on with status 'a' see the query after the if($_SESSION etc. ?
I know i have not stated the $_SESSION var yet but thats where iam stuck, i dont know what function to give the var.

Here's the code ;

________________________________________

<?php
$query = mysql_query("SELECT * FROM `inlogsysteem`");



while($rij = mysql_fetch_assoc($query))
{
echo "
<tr>
<td>".ucfirst($rij['username'])."</td>
<td>";
if($rij['status'] == "a") { echo "<span style=\"color:#F00000;\"><b>Admin</b></span>"; }
if($rij['status'] == "m") { echo "<span style=\"color:#102030;\"><b>Moderator</b></span>"; }
if($rij['status'] == "n") { echo "Normale Member"; }
echo "</td>";
echo "<td>";
echo "".$rij['email']."<br>";
echo "</td>";
echo "<td>";
echo "</td>
</tr>
";
}
if($_SESSION['login'] == "1" && $_SESSION['status'] == "a")
{
echo "
<tr>
<td>".ucfirst($rij['username'])."</td>
<td>";
if($rij['status'] == "a") { echo "<span style=\"color:#F00000;\"><b>Admin</b></span>"; }
if($rij['status'] == "m") { echo "<span style=\"color:#102030;\"><b>Moderator</b></span>"; }
if($rij['status'] == "n") { echo "Normale Member"; }
echo "</td>";
echo "<td>";
echo "".$rij['email']."<br>";
echo "</td>";
echo "<td>";
echo "".$rij['password']."<br>";
echo "</td>
</tr>
";
}
?>

Try using x86 Assembly first.

bump

It's obvious the correct solution is to use JavaScript and read my blog.

ITT Dutch people.

http://php.net/session_start

daat daat daaaaaaat daaaaat data daaaaaaat

YHBT

>>1
Your code is beautiful. I can't stop looking at it.

Lain.

11 Name: Anonymous 2011-01-31 21:16

<-- check em dubz