$ python
Python 2.5.2 (r252:60911, Nov 14 2008, 19:46:32)
[GCC 4.3.2] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> for i in range(0,1): print ("LOL FIOC")
...
LOL FIOC
>>>
YOU SAID THERE WOULD BE FORCED INDENTATION OF CODE, /prog/.
I don't believe you faggots anymore.
Name:
Anonymous2008-12-16 7:11
[code]
$ python
Python 2.5.2 (r252:60911, Nov 14 2008, 19:46:32)
[GCC 4.3.2] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> for i in xrange(0,3): \
... print('Troll Detected'); \
... print('srsly')
...
Troll Detected
srsly
Troll Detected
srsly
Troll Detected
srsly
>>>
[code]
Name:
Anonymous2008-12-16 7:12
Write this in your FIOC without FIOC [m]for(i=0;i<10;i++)
for(j=0;j<10;j++)
for(k=0;k<10;k++){
v[i][j][k]=func(i,j,k);
}[/m]
Name:
Anonymous2008-12-16 18:14
>>3
I will, if you give a definition of v, and also learn how not to fail at bbcode.