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LISP [part '7]

Name: Anonymous 2008-09-13 22:28

LISP

Name: Anonymous 2009-06-04 3:51

>>768
lisp can't do
function impossible_in_lisp()
{ var o = '';
  var i = 0;
  for(var c = arguments.callee.caller; c; c = c.caller)
    o += (i++) + ': ' + c.toString() + '\n';
  alert(o); }


or
function(n)
{ return (function(i)
  { return i==1?0:arguments.callee(i-1)+(function(i)
    { return i==1?1:arguments.callee.caller(i-1) })(i-1) })(n+1) }

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