Why won't this compile?

#include <iostream>

using namespace std;

main()
{
int x = 0;
int i = 6;
for (int i = 6; i > 0, i--, x++)
(
         cout << "i = " << i << endl;
         cout << "x = " << x << endl;
)
         if (x != i)
            continue;

cout << "This is now equal." << endl;    

}

You are shadowing i and breaking the syntax of the for loop. 

With minimal changes:
int i = 6;
for(i; i-- > 0; x++) {

Sigh. Troll harder.

You've been (Lisp)ing too hard.

>>1
missing return type for main (should be int)
a for loop needs three parts (separated by ;), not just two
blocks are delimited by {}, not ()
can't use continue outside of loops

missing return type for main (should be int)
This ain't no Haskell, kid.

>>6
This ain't no dog, Haskell.

9 Name: Anonymous 2010-10-26 21:42

12 Name: Anonymous 2010-12-17 1:36

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Are you a NIGGER?
Are you a GAY NIGGER?

If you answered "Yes" to all of the above questions, then GNAA (GAY NIGGER ASSOCIATION OF AMERICA) might be exactly what you've been looking for!

13 Name: Anonymous 2011-02-04 19:00

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Don't change these.

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