Java question

I was wondering if any of you java geeks could help me with the following:

package testproject;
import java.util.Scanner;

public class Main {

    public static void main(String[] args) {
      
        doubleClass l = new doubleClass();
       
        while(true)
        {
            l.countUp();
            System.out.println(l.getNumber());
            Scanner in = new Scanner(System.in);
            // wait for <Enter> to be pressed
            in.nextLine();
        }
    }
}

package testproject;
public class doubleClass {

    private double number;
   
    public doubleClass()
    {
        number = 0;
    }
   
    public void countUp()
    {
        number += 0.01;  
    }
   
    public double getNumber()
    {
        return number;
    }
}

So basically a very simple program to test a double.
The problem is that the number fucks up at some points.
e.g. instead of printing 0.06 it prints 0.060000000000000005
Why the fuck is this and how can I get it to work normally
like in c or c++?

HAVE YOU READ YOUR http://docs.sun.com/source/806-3568/ncg_goldberg.html TODAY?

Then why does it work flawlessly in c++?

you cant represent every number so floating point gives an aproximation. Maybe java uses diferent exponent or fraction lenght than c++ in his representation.
anyways,c++ doesnt do it flawlessly, on my box prints
0.000000000000000
0.009999999776483
0.019999999552965
0.029999999329448
0.039999999105930
0.050000000745058
0.060000002384186
0.070000000298023

Did you just call us Java geeks?

>>4
That's weird because the following prints it just as I want it:

#include <stdlib.h>
#include <iostream>
#include <string>

double a = 0;

int main(int argc, char** argv) {
   
    while(true)
    {
        a += 0.01;
        std::cout << "The number: "; //+ a << std::endl();
        std::cout << a;
        std::string dummy;
        std::getline(std::cin, dummy);

    }
    return (EXIT_SUCCESS);
}

Perhaps c++ has some built in rounding methods?

But any suggestions as to how I should count a number with 3 decimals in Java?

>>1
Scanner in = new Scanner(System.in);
LOL

>>6
try putting
std::cout.precision(30);
before the while and see what that prints

Here's the problem:

You're using Java................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................

I'm sorry, but we only program in C# around these parts. VB.NET is also acceptable.
I'd ask you to look up roundoff errors and out.format, but you wouldn't understand it anyway.

I'm sorry, but we only program in Lisp around these parts. Haskell is also acceptable.
I'd ask you to look up monads and higher-order functions, but you wouldn't understand it anyway.

Use BigDecimals if you want to do stuff like that.
Or use rational numbers.
Or use a computer that operates in base 10.

Anyway, you could read some papers on floating point

Or use a computer that operates in base 10.

Too bad the JVM can't.

BCD FTW

Using one to type this is a   liar and a   community in denial   about my assassination   of the Sussman   of the relationship   between dqn voltages.