I am stupid

Ok... I have been reading a book on programming and some such and I wanted to make a simple function. I am doing it wrong though.
This won't let me refer to "addition" more than once or else the compiler throws a bitch fit. Why is that?
#include <cstdlib>
#include <iostream>

using namespace std;

int main ()
{
    char MenuA;
    cout << "please enter A for addition: ";
    cin >> MenuA;
    float x, y, aso;
   
    double addition ();
    {
           cout << "please enter the first number to be added: ";
           cin >> x;
           cout << "please enter the second number to be added: ";
           cin >> y;
          
           aso = x + y;
          
           cout << "the solution is: " << aso;
         
          
           }
   
   
    if ( MenuA == 'A')
    {
         addition;
         }
         else if (MenuA != 'A')
         {
              cout << "you must enter A";
              }
  
             
              return 0;
              }

>>1
Ok... I have been reading a book on programming and some such
It'd better be called SICP or you're in for some trouble!

addition; is a reference, not call.

>>3
then how would I call it? or what ever

why the fuck didn't you return anything from the addition function and why is it in main?

>>5
read the thread subject

addition(); or addition(void);
The code looks strange too - Why do you define the function in the middle of main(), and check if (MenuA == 'A') after it?

ok a bit better


#include <cstdlib>
#include <iostream>

using namespace std;


double addition(void)
{
float x, y, aso;
       cout << "please enter the first number to be added: ";
           cin >> x;
           cout << "please enter the second number to be added: ";
           cin >> y;
          
           aso = x + y;
          
           cout << "the solution is: " << aso;
           }

int main ()
{
    char MenuA;
    cout << "please enter A for addition: ";
    cin >> MenuA;

   
   
    if ( MenuA == 'A')
    {
         addition();
         }
         else if (MenuA != 'A')
         {
              cout << "you must enter A";
              }
  
             
              return 0;
              }

Try reading the book again.


double add ()
{
  in: x
  in: y
  return x + y
}

main ()
{
  add ()
}

more like this faggot.

woooo now it runs until you don't enter 'y'
 :D
#include <cstdlib>
#include <iostream>

using namespace std;


double addition(void)
{
float x, y, aso;
       cout << "please enter the first number to be added: ";
           cin >> x;
           cout << "please enter the second number to be added: ";
           cin >> y;
          
           aso = x + y;
          
           cout << "the solution is: " << aso << "\n";
          
           }

int main ()
{
char yns;
    char MenuA;
    cout << "please enter A for addition: ";
    cin >> MenuA;

   
   
    if ( MenuA == 'A')
    {
         addition();
         }
         else if (MenuA != 'A')
         {
              cout << "you must enter A";
              }
    cout << "would you like to go again? (y/n): ";
    cin >> yns;
   
    do
    {
        addition();
         cout << "would you like to go again? (y/n): ";
    cin >> yns;
        } while (yns == 'y');
     }

>>11
jesus christ learn how to indent, faggot.

>>1
Hello and welcome to our community. if/else menus are not elegant and even considered harmful, try to refrain using them and use switch().

>>13
Hello and welcome to our community. if/else menus are not elegant and even considered harmful, try to refrain from using them and use switch().

  

>>12

#include <cstdlib>
#include <iostream>
using namespace std;
double addition(void)
{float x, y, aso; cout << "please enter the first number to be added: "; cin >> x;
 cout << "please enter the second number to be added: "; cin >> y;
 aso = x + y; cout << "the solution is: " << aso << "\n";}
int main ()
{
char yns;
char MenuA;
cout << "please enter A for addition: "; cin >> MenuA;
if ( MenuA == 'A'){addition();}
else if (MenuA != 'A')
{cout << "you must enter A";}
cout << "would you like to go again? (y/n): "; cin >> yns;
do{ addition(); cout << "would you like to go again? (y/n): "; cin >> yns; } while (yns == 'y');}

Stop posting.

>>13,14
Produces the exact same compiled code in any modern compiler.

>>17
Back to /b/, please.

>>17
Switches can be optimized with jump tables, depending on the cases. No modern compiler compiler optimizes if-else

I added some functions... but the way I am trying to get the common denominator isn't accurate enough :(

#include <cstdlib>
#include <iostream>
using namespace std;
float addition(void)
{float x, y, aso; cout << "please enter the first number to be added: "; cin >> x;
 cout << "please enter the second number to be added: "; cin >> y;
 aso = x + y; cout << "the solution is: " << aso << "\n";}
float division (void)
{ float x, y, dso;
cout << "please enter the numerator "; cin >> x;
 cout << "please enter the denominator: "; cin >> y;
 dso = x/y; cout << "the solution is: " << dso << "\n";}
float subtraction (void)
{ float x, y, sso;
cout << "please enter the first number to be subtracted: "; cin >> x;
 cout << "please enter the second number to be subtracted: "; cin >> y;
 sso = x - y; cout << "the solution is: " << sso << "\n";}
float multiplication (void)
{ float x, y, mso;
cout << "please enter the first number to be multiplied: "; cin >> x;
 cout << "please enter the second number to be multiplied: "; cin >> y;
 mso = x * y; cout << "the solution is: " << mso << "\n";}
float degrees_to_radians (void)
{float radianst, radiansb;
 int dgrs, cdr;
 cdr = 1;
 cout << "please enter degrees to be converted to radians: " ;
 cin >> dgrs;   
 while (dgrs%cdr == 0 && 180%cdr == 0)
 {cdr++;}
        radianst = dgrs/cdr;
        radiansb = 180/cdr;
        cout << dgrs << "in radians is: " << radianst << "pi/" << radiansb << "\n";
        }
int main ()
{
char yns;
char Menu;
cout << "menu: " << "\n";
cout << "A: Addition\n";
cout << "D: Division\n";
cout << "S: Subtraction\n";
cout << "M: Multiplication\n";
cout << "R: Degrees to radians\n";
cin >> Menu;
switch (Menu)
{
       case 'A':
       addition();
       break;
       case 'D':
       division();
       break;
       case 'S':
       subtraction();
       break;
       case 'M':
       multiplication();
       break;
       case 'R':
       degrees_to_radians();
       break;
       }
       return main();
       }

fuck
this

HOLY FUCKING SHIT

Seriously, get Emacs, and paste the code in, then hit tab on every line. It will AUTO-INDENT IT FOR YOU.

>>22
indentation shouldn't really matter... if it matters that much to you go use python or something you faggot.

>>23
I can't read this faggot's code.

Which part of `Stop posting' did you not understand?

>>25
You're confusing proper.stringQuotes with proper.charQuotes, Sir.

>>26
I'm not. Also shitCase is for niggers.

if you have no arguments for a function, you need to have void in the parens.

i.e main(void), whatever(void)

Fuck off, learn C before Sepples.

>>22
Uh, it's emacs. Try C-M-\. Why the FUCK would someone TAB each line?

Fuck off, learn C++ before C.

Stop posting.

You are stupid.
Your code is shit.
You're not learning anything, because you're stupid. Your code will be shit until you gtfo and become less stupid.

This is why you don't learn C or a C-like language as your first programming language.

>>30
Because they're scared of hitting ctrl+alt+bksp.

>>34
I see what you did there

>>35
It's true. I actually did hit CAB once. And I lost a lot of work too. It's a good thing writing Lisp code is just as much fun the second time around. ;_;

You realize you can turn off and rebind that key combo?

When I would ever hit shift-alt-meta-super-k, I have no idea, but I know I will NEVER accidentally hit it. Ever.

cdr = 1;
cdr

MY OTHER CAR!

>>36
Section "ServerFlags"
    Option "DontZap" "true"
EndSection

Lain.